Hello everyone. This lesson we will tell the integrate of $\int \frac{x}{x-1}dx$.
What is the integral of x/x-1?
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integral of x/x-1
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First we separate the expression.
So;
$\frac{x}{x-1}=1+\frac{1}{x-1}$
So our answer;
$\int \frac{x}{x-1}dx=\int 1 dx+ \int \frac{1}{x-1}dx=x+ln|x-1|+C$
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