Derivative of $(x^2-4)^3$ | Find the derivative of the function $f(x)=(x^2-4)^3$

Find the derivative of the function $f(x)=(x^2-4)^3$

Solution

We need to derive the composite function $u^3$, where $u=x^2-4$. Consequently, we need to use the chain derivative.

$f'(x)=[(x^2-4)^3]'$

$=3.(x^2-4)^2.(x^2-4)'$

$=3.(x^2-4)^2.2x$

$=6x.(x^2-4)^2$